12x^2+8x-480=0

Solution for 12x^2+8x-480=0 equation:

12x^2+8x-480=0

a = 12; b = 8; c = -480;
Δ = b2-4ac
Δ = 82-4·12·(-480)
Δ = 23104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{23104}=152$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-152}{2*12}=\frac{-160}{24}
=-6+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+152}{2*12}=\frac{144}{24}
=6
$